Base | Representation |
---|---|
bin | 1110010010110100100010… |
… | …11101101010001010101100 |
3 | 11010021222002120222101110111 |
4 | 13021122101131222022230 |
5 | 13104444301323041330 |
6 | 150504043113145404 |
7 | 6422650214211532 |
oct | 711322135521254 |
9 | 133258076871414 |
10 | 31433011143340 |
11 | a019735373994 |
12 | 3637b179bb264 |
13 | 14701741c4821 |
14 | 7a9519ca8152 |
15 | 3979a10a832a |
hex | 1c969176a2ac |
31433011143340 has 24 divisors (see below), whose sum is σ = 66022392178512. Its totient is φ = 12570715166400.
The previous prime is 31433011143277. The next prime is 31433011143397. The reversal of 31433011143340 is 4334111033413.
It is a happy number.
It is a super-2 number, since 2×314330111433402 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155477139 + ... + 155679178.
It is an arithmetic number, because the mean of its divisors is an integer number (2750933007438).
Almost surely, 231433011143340 is an apocalyptic number.
It is an amenable number.
31433011143340 is an abundant number, since it is smaller than the sum of its proper divisors (34589381035172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31433011143340 is a wasteful number, since it uses less digits than its factorization.
31433011143340 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 311161377 (or 311161375 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 31433011143340 its reverse (4334111033413), we get a palindrome (35767122176753).
The spelling of 31433011143340 in words is "thirty-one trillion, four hundred thirty-three billion, eleven million, one hundred forty-three thousand, three hundred forty".
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