Base | Representation |
---|---|
bin | 101101101111011011111… |
… | …000001001100111011101 |
3 | 102010111102200100202022200 |
4 | 231233123320021213131 |
5 | 402444444331220013 |
6 | 10404003334402113 |
7 | 443045103232440 |
oct | 55573370114735 |
9 | 12114380322280 |
10 | 3143310023133 |
11 | 1002085620225 |
12 | 429240200339 |
13 | 19a54a0a3467 |
14 | ac1cbd8d657 |
15 | 56b70d47e73 |
hex | 2dbdbe099dd |
3143310023133 has 24 divisors (see below), whose sum is σ = 5202026688768. Its totient is φ = 1791652766112.
The previous prime is 3143310023123. The next prime is 3143310023153. The reversal of 3143310023133 is 3313200133413.
3143310023133 is a `hidden beast` number, since 3 + 14 + 331 + 0 + 0 + 2 + 313 + 3 = 666.
It is not a de Polignac number, because 3143310023133 - 29 = 3143310022621 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3143310023097 and 3143310023106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3143310023123) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 62813541 + ... + 62863562.
It is an arithmetic number, because the mean of its divisors is an integer number (216751112032).
Almost surely, 23143310023133 is an apocalyptic number.
It is an amenable number.
3143310023133 is a deficient number, since it is larger than the sum of its proper divisors (2058716665635).
3143310023133 is a wasteful number, since it uses less digits than its factorization.
3143310023133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125677513 (or 125677510 counting only the distinct ones).
The product of its (nonzero) digits is 5832, while the sum is 27.
Adding to 3143310023133 its reverse (3313200133413), we get a palindrome (6456510156546).
The spelling of 3143310023133 in words is "three trillion, one hundred forty-three billion, three hundred ten million, twenty-three thousand, one hundred thirty-three".
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