Base | Representation |
---|---|
bin | 1110010010110100101111… |
… | …00110000100110101101010 |
3 | 11010021222100202112201011011 |
4 | 13021122113212010311222 |
5 | 13110000004141404114 |
6 | 150504101230054134 |
7 | 6422652603455266 |
oct | 711322746046552 |
9 | 133258322481134 |
10 | 31433114013034 |
11 | a019788445468 |
12 | 3637b4634a34a |
13 | 147018c601576 |
14 | 7a95298050a6 |
15 | 3979aa1281c4 |
hex | 1c9697984d6a |
31433114013034 has 8 divisors (see below), whose sum is σ = 47509592172768. Its totient is φ = 15596583288780.
The previous prime is 31433114012987. The next prime is 31433114013097. The reversal of 31433114013034 is 43031041133413.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 31433114012987 and 31433114013005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59986858542 + ... + 59986859065.
It is an arithmetic number, because the mean of its divisors is an integer number (5938699021596).
Almost surely, 231433114013034 is an apocalyptic number.
31433114013034 is a deficient number, since it is larger than the sum of its proper divisors (16076478159734).
31433114013034 is a wasteful number, since it uses less digits than its factorization.
31433114013034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119973717740.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 31433114013034 its reverse (43031041133413), we get a palindrome (74464155146447).
The spelling of 31433114013034 in words is "thirty-one trillion, four hundred thirty-three billion, one hundred fourteen million, thirteen thousand, thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.311 sec. • engine limits •