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314331431 is a prime number
BaseRepresentation
bin10010101111000…
…101000100100111
3210220110200122212
4102233011010213
51120432101211
651105114035
710534526111
oct2257050447
9726420585
10314331431
11151482947
128932891b
135017803b
142da643b1
151c8e038b
hex12bc5127

314331431 has 2 divisors, whose sum is σ = 314331432. Its totient is φ = 314331430.

The previous prime is 314331401. The next prime is 314331449. The reversal of 314331431 is 134133413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 314331431 - 214 = 314315047 is a prime.

It is a super-3 number, since 3×3143314313 (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 314331397 and 314331406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314331401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157165715 + 157165716.

It is an arithmetic number, because the mean of its divisors is an integer number (157165716).

Almost surely, 2314331431 is an apocalyptic number.

314331431 is a deficient number, since it is larger than the sum of its proper divisors (1).

314331431 is an equidigital number, since it uses as much as digits as its factorization.

314331431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 23.

The square root of 314331431 is about 17729.3945469099. The cubic root of 314331431 is about 679.9274944319.

Adding to 314331431 its reverse (134133413), we get a palindrome (448464844).

The spelling of 314331431 in words is "three hundred fourteen million, three hundred thirty-one thousand, four hundred thirty-one".