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31433203141 = 71442721171
BaseRepresentation
bin11101010001100100…
…001001110111000101
310000010122010011110221
4131101210021313011
51003333400000031
622235030344341
72161641550444
oct352144116705
9100118104427
1031433203141
111237025083a
126112abb0b1
132c6c29a7b2
141742920d5b
15c3e87ba11
hex751909dc5

31433203141 has 4 divisors (see below), whose sum is σ = 31875924384. Its totient is φ = 30990481900.

The previous prime is 31433203121. The next prime is 31433203181. The reversal of 31433203141 is 14130233413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31433203141 - 27 = 31433203013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31433203111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221360515 + ... + 221360656.

It is an arithmetic number, because the mean of its divisors is an integer number (7968981096).

Almost surely, 231433203141 is an apocalyptic number.

It is an amenable number.

31433203141 is a deficient number, since it is larger than the sum of its proper divisors (442721243).

31433203141 is an equidigital number, since it uses as much as digits as its factorization.

31433203141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 442721242.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 31433203141 its reverse (14130233413), we get a palindrome (45563436554).

The spelling of 31433203141 in words is "thirty-one billion, four hundred thirty-three million, two hundred three thousand, one hundred forty-one".

Divisors: 1 71 442721171 31433203141