Base | Representation |
---|---|
bin | 101101101111011100100… |
… | …000010111001001010001 |
3 | 102010111110102012022002110 |
4 | 231233130200113021101 |
5 | 403000010031024210 |
6 | 10404004352335533 |
7 | 443045261644635 |
oct | 55573440271121 |
9 | 12114412168073 |
10 | 3143320564305 |
11 | 100209056aa39 |
12 | 4292438445a9 |
13 | 19a54c32443c |
14 | ac1cd534dc5 |
15 | 56b71c2b420 |
hex | 2dbdc817251 |
3143320564305 has 48 divisors (see below), whose sum is σ = 5344404145920. Its totient is φ = 1577278230528.
The previous prime is 3143320564259. The next prime is 3143320564331. The reversal of 3143320564305 is 5034650233413.
3143320564305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3143320564305 - 215 = 3143320531537 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12564681 + ... + 12812409.
It is an arithmetic number, because the mean of its divisors is an integer number (111341753040).
Almost surely, 23143320564305 is an apocalyptic number.
It is an amenable number.
3143320564305 is a deficient number, since it is larger than the sum of its proper divisors (2201083581615).
3143320564305 is a wasteful number, since it uses less digits than its factorization.
3143320564305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 250698 (or 250681 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 3143320564305 its reverse (5034650233413), we get a palindrome (8177970797718).
The spelling of 3143320564305 in words is "three trillion, one hundred forty-three billion, three hundred twenty million, five hundred sixty-four thousand, three hundred five".
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