Base | Representation |
---|---|
bin | 101101101111011101000… |
… | …101111000111011010101 |
3 | 102010111111002201002212201 |
4 | 231233131011320323111 |
5 | 403000020040331010 |
6 | 10404005343244501 |
7 | 443045441400163 |
oct | 55573505707325 |
9 | 12114432632781 |
10 | 3143330402005 |
11 | 100209607a172 |
12 | 429246ba9731 |
13 | 19a55138a171 |
14 | ac1d0976233 |
15 | 56b72a2123a |
hex | 2dbdd178ed5 |
3143330402005 has 4 divisors (see below), whose sum is σ = 3771996482412. Its totient is φ = 2514664321600.
The previous prime is 3143330401997. The next prime is 3143330402027. The reversal of 3143330402005 is 5002040333413.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 439824955249 + 2703505446756 = 663193^2 + 1644234^2 .
It is not a de Polignac number, because 3143330402005 - 23 = 3143330401997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314333040196 + ... + 314333040205.
It is an arithmetic number, because the mean of its divisors is an integer number (942999120603).
Almost surely, 23143330402005 is an apocalyptic number.
It is an amenable number.
3143330402005 is a deficient number, since it is larger than the sum of its proper divisors (628666080407).
3143330402005 is an equidigital number, since it uses as much as digits as its factorization.
3143330402005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 628666080406.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 3143330402005 its reverse (5002040333413), we get a palindrome (8145370735418).
The spelling of 3143330402005 in words is "three trillion, one hundred forty-three billion, three hundred thirty million, four hundred two thousand, five".
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