3144110012503 has 2 divisors, whose sum is σ = 3144110012504. Its totient is φ = 3144110012502.

The previous prime is 3144110012497. The next prime is 3144110012507. The reversal of 3144110012503 is 3052100114413.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3144110012503 is a prime.

It is a super-2 number, since 2×3144110012503² (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3144110012507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572055006251 + 1572055006252.

It is an arithmetic number, because the mean of its divisors is an integer number (1572055006252).

Almost surely, 2^{3144110012503} is an apocalyptic number.

3144110012503 is a deficient number, since it is larger than the sum of its proper divisors (1).

3144110012503 is an equidigital number, since it uses as much as digits as its factorization.

3144110012503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 3144110012503 its reverse (3052100114413), we get a palindrome (6196210126916).

The spelling of 3144110012503 in words is "three trillion, one hundred forty-four billion, one hundred ten million, twelve thousand, five hundred three".