Base | Representation |
---|---|
bin | 101101110001000011110… |
… | …110110110111100000011 |
3 | 102010122221020221010012121 |
4 | 231301003312312330003 |
5 | 403012032423434242 |
6 | 10404452413105111 |
7 | 443136245201422 |
oct | 55610366667403 |
9 | 12118836833177 |
10 | 3145054514947 |
11 | 10028a03117a4 |
12 | 429648488197 |
13 | 19a767629c37 |
14 | ac3159372b9 |
15 | 56c24089667 |
hex | 2dc43db6f03 |
3145054514947 has 2 divisors, whose sum is σ = 3145054514948. Its totient is φ = 3145054514946.
The previous prime is 3145054514911. The next prime is 3145054515061. The reversal of 3145054514947 is 7494154505413.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3145054514947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3145054514894 and 3145054514903.
It is not a weakly prime, because it can be changed into another prime (3145054514647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1572527257473 + 1572527257474.
It is an arithmetic number, because the mean of its divisors is an integer number (1572527257474).
Almost surely, 23145054514947 is an apocalyptic number.
3145054514947 is a deficient number, since it is larger than the sum of its proper divisors (1).
3145054514947 is an equidigital number, since it uses as much as digits as its factorization.
3145054514947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048000, while the sum is 52.
The spelling of 3145054514947 in words is "three trillion, one hundred forty-five billion, fifty-four million, five hundred fourteen thousand, nine hundred forty-seven".
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