Base | Representation |
---|---|
bin | 1011101110110001… |
… | …1101000010111101 |
3 | 22010110101101220022 |
4 | 2323230131002331 |
5 | 22422120231301 |
6 | 1240245501525 |
7 | 141014665511 |
oct | 27354350275 |
9 | 8113341808 |
10 | 3148992701 |
11 | 1376584908 |
12 | 73a7118a5 |
13 | 3b251caba |
14 | 21c30c141 |
15 | 1366c4d1b |
hex | bbb1d0bd |
3148992701 has 2 divisors, whose sum is σ = 3148992702. Its totient is φ = 3148992700.
The previous prime is 3148992677. The next prime is 3148992703. The reversal of 3148992701 is 1072998413.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3136560025 + 12432676 = 56005^2 + 3526^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3148992701 is a prime.
Together with 3148992703, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3148992703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1574496350 + 1574496351.
It is an arithmetic number, because the mean of its divisors is an integer number (1574496351).
Almost surely, 23148992701 is an apocalyptic number.
It is an amenable number.
3148992701 is a deficient number, since it is larger than the sum of its proper divisors (1).
3148992701 is an equidigital number, since it uses as much as digits as its factorization.
3148992701 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 44.
The square root of 3148992701 is about 56115.8863513711. The cubic root of 3148992701 is about 1465.7409385910.
The spelling of 3148992701 in words is "three billion, one hundred forty-eight million, nine hundred ninety-two thousand, seven hundred one".
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