Base | Representation |
---|---|
bin | 11101010101100011… |
… | …010110001000010011 |
3 | 10000022021222212212122 |
4 | 131111203112020103 |
5 | 1004003011200430 |
6 | 22245420244455 |
7 | 2163413301401 |
oct | 352543261023 |
9 | 100267885778 |
10 | 31500100115 |
11 | 123a4a924a0 |
12 | 61313a072b |
13 | 2c800c0ac3 |
14 | 174b776471 |
15 | c45692ee5 |
hex | 7558d6213 |
31500100115 has 16 divisors (see below), whose sum is σ = 41242508640. Its totient is φ = 22905822720.
The previous prime is 31500100111. The next prime is 31500100129. The reversal of 31500100115 is 51100100513.
It is not a de Polignac number, because 31500100115 - 22 = 31500100111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31500100093 and 31500100102.
It is not an unprimeable number, because it can be changed into a prime (31500100111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 376541 + ... + 452529.
It is an arithmetic number, because the mean of its divisors is an integer number (2577656790).
Almost surely, 231500100115 is an apocalyptic number.
31500100115 is a deficient number, since it is larger than the sum of its proper divisors (9742408525).
31500100115 is a wasteful number, since it uses less digits than its factorization.
31500100115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83542.
The product of its (nonzero) digits is 75, while the sum is 17.
Adding to 31500100115 its reverse (51100100513), we get a palindrome (82600200628).
The spelling of 31500100115 in words is "thirty-one billion, five hundred million, one hundred thousand, one hundred fifteen".
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