Base | Representation |
---|---|
bin | 101101110101110111011… |
… | …001000111010100000111 |
3 | 102011011020211121012121212 |
4 | 231311313121013110013 |
5 | 403103114302201411 |
6 | 10411104405002035 |
7 | 443411146020212 |
oct | 55656731072407 |
9 | 12134224535555 |
10 | 3150214100231 |
11 | 1004aa8808570 |
12 | 42a6483b331b |
13 | 19b0aa562593 |
14 | ac684c9a779 |
15 | 56e2701568b |
hex | 2dd77647507 |
3150214100231 has 32 divisors (see below), whose sum is σ = 3508016758848. Its totient is φ = 2805002403840.
The previous prime is 3150214100221. The next prime is 3150214100237. The reversal of 3150214100231 is 1320014120513.
It is a cyclic number.
It is not a de Polignac number, because 3150214100231 - 238 = 2875336193287 is a prime.
It is a super-2 number, since 2×31502141002312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3150214100197 and 3150214100206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3150214100237) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 81607271 + ... + 81645863.
It is an arithmetic number, because the mean of its divisors is an integer number (109625523714).
Almost surely, 23150214100231 is an apocalyptic number.
3150214100231 is a deficient number, since it is larger than the sum of its proper divisors (357802658617).
3150214100231 is a wasteful number, since it uses less digits than its factorization.
3150214100231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39491.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 3150214100231 its reverse (1320014120513), we get a palindrome (4470228220744).
The spelling of 3150214100231 in words is "three trillion, one hundred fifty billion, two hundred fourteen million, one hundred thousand, two hundred thirty-one".
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