Base | Representation |
---|---|
bin | 1001001010110010100… |
… | …01010110000000111101 |
3 | 1010010011000010222100211 |
4 | 10211121101112000331 |
5 | 20130140231101303 |
6 | 400420053152421 |
7 | 31521513430555 |
oct | 4453121260075 |
9 | 1103130128324 |
10 | 315030331453 |
11 | 111670455832 |
12 | 5107b02b711 |
13 | 23926a37766 |
14 | 113673c0165 |
15 | 82dbeb566d |
hex | 495945603d |
315030331453 has 2 divisors, whose sum is σ = 315030331454. Its totient is φ = 315030331452.
The previous prime is 315030331403. The next prime is 315030331477. The reversal of 315030331453 is 354133030513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 292764319929 + 22266011524 = 541077^2 + 149218^2 .
It is a cyclic number.
It is not a de Polignac number, because 315030331453 - 237 = 177591377981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315030331403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157515165726 + 157515165727.
It is an arithmetic number, because the mean of its divisors is an integer number (157515165727).
Almost surely, 2315030331453 is an apocalyptic number.
It is an amenable number.
315030331453 is a deficient number, since it is larger than the sum of its proper divisors (1).
315030331453 is an equidigital number, since it uses as much as digits as its factorization.
315030331453 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24300, while the sum is 31.
Adding to 315030331453 its reverse (354133030513), we get a palindrome (669163361966).
The spelling of 315030331453 in words is "three hundred fifteen billion, thirty million, three hundred thirty-one thousand, four hundred fifty-three".
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