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315035243381 is a prime number
BaseRepresentation
bin1001001010110011001…
…00000101001101110101
31010010011100101112021002
410211121210011031311
520130143010242011
6400420350333045
731521603246215
oct4453144051565
91103140345232
10315035243381
11111673200181
12510807ba185
1323927a67421
1411367cdc245
1582dc635c3b
hex4959905375

315035243381 has 2 divisors, whose sum is σ = 315035243382. Its totient is φ = 315035243380.

The previous prime is 315035243363. The next prime is 315035243401. The reversal of 315035243381 is 183342530513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 234634640881 + 80400602500 = 484391^2 + 283550^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315035243381 is a prime.

It is a super-2 number, since 2×3150352433812 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315035243311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157517621690 + 157517621691.

It is an arithmetic number, because the mean of its divisors is an integer number (157517621691).

Almost surely, 2315035243381 is an apocalyptic number.

It is an amenable number.

315035243381 is a deficient number, since it is larger than the sum of its proper divisors (1).

315035243381 is an equidigital number, since it uses as much as digits as its factorization.

315035243381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 315035243381 its reverse (183342530513), we get a palindrome (498377773894).

The spelling of 315035243381 in words is "three hundred fifteen billion, thirty-five million, two hundred forty-three thousand, three hundred eighty-one".