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3150475107145 = 5630095021429
BaseRepresentation
bin101101110110000110111…
…100110001101101001001
3102011011221000201201210121
4231312012330301231021
5403104133111412040
610411150331143241
7443420465364262
oct55660674615511
912134830651717
103150475107145
111005122079963
1242a6bb8a4b21
1319b11c659c42
14ac6ab7dd969
1556e3edc0c4a
hex2dd86f31b49

3150475107145 has 4 divisors (see below), whose sum is σ = 3780570128580. Its totient is φ = 2520380085712.

The previous prime is 3150475107127. The next prime is 3150475107161. The reversal of 3150475107145 is 5417015740513.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1647369683001 + 1503105424144 = 1283499^2 + 1226012^2 .

It is a cyclic number.

It is not a de Polignac number, because 3150475107145 - 217 = 3150474976073 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315047510710 + ... + 315047510719.

It is an arithmetic number, because the mean of its divisors is an integer number (945142532145).

Almost surely, 23150475107145 is an apocalyptic number.

It is an amenable number.

3150475107145 is a deficient number, since it is larger than the sum of its proper divisors (630095021435).

3150475107145 is an equidigital number, since it uses as much as digits as its factorization.

3150475107145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 630095021434.

The product of its (nonzero) digits is 294000, while the sum is 43.

The spelling of 3150475107145 in words is "three trillion, one hundred fifty billion, four hundred seventy-five million, one hundred seven thousand, one hundred forty-five".

Divisors: 1 5 630095021429 3150475107145