Base | Representation |
---|---|
bin | 1001001010111011010… |
… | …10010111100101011001 |
3 | 1010010100010202202002022 |
4 | 10211131222113211121 |
5 | 20130313111002340 |
6 | 400431244144225 |
7 | 31523366544641 |
oct | 4453552274531 |
9 | 1103303682068 |
10 | 315104000345 |
11 | 1116a8aa2312 |
12 | 5109b838075 |
13 | 2393908c214 |
14 | 113730b9521 |
15 | 82e36b83b5 |
hex | 495da97959 |
315104000345 has 4 divisors (see below), whose sum is σ = 378124800420. Its totient is φ = 252083200272.
The previous prime is 315104000333. The next prime is 315104000369. The reversal of 315104000345 is 543000401513.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 543000401513 = 17 ⋅31941200089.
It can be written as a sum of positive squares in 2 ways, for example, as 150562624576 + 164541375769 = 388024^2 + 405637^2 .
It is a cyclic number.
It is not a de Polignac number, because 315104000345 - 220 = 315102951769 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31510400030 + ... + 31510400039.
It is an arithmetic number, because the mean of its divisors is an integer number (94531200105).
Almost surely, 2315104000345 is an apocalyptic number.
It is an amenable number.
315104000345 is a deficient number, since it is larger than the sum of its proper divisors (63020800075).
315104000345 is an equidigital number, since it uses as much as digits as its factorization.
315104000345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63020800074.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 315104000345 its reverse (543000401513), we get a palindrome (858104401858).
The spelling of 315104000345 in words is "three hundred fifteen billion, one hundred four million, three hundred forty-five", and thus it is an aban number.
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