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315114133 = 599526067
BaseRepresentation
bin10010110010000…
…100001010010101
3210221221110022211
4102302010022111
51121132123013
651133553421
710544266045
oct2262041225
9727843284
10315114133
11151967a04
1289645871
1350390389
142dbc9725
151c9e723d
hex12c84295

315114133 has 4 divisors (see below), whose sum is σ = 315640800. Its totient is φ = 314587468.

The previous prime is 315114131. The next prime is 315114143. The reversal of 315114133 is 331411513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 315114133 - 21 = 315114131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315114131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 262435 + ... + 263632.

It is an arithmetic number, because the mean of its divisors is an integer number (78910200).

Almost surely, 2315114133 is an apocalyptic number.

It is an amenable number.

315114133 is a deficient number, since it is larger than the sum of its proper divisors (526667).

315114133 is an equidigital number, since it uses as much as digits as its factorization.

315114133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 526666.

The product of its digits is 540, while the sum is 22.

The square root of 315114133 is about 17751.4543911196. The cubic root of 315114133 is about 680.4913785449.

Adding to 315114133 its reverse (331411513), we get a palindrome (646525646).

The spelling of 315114133 in words is "three hundred fifteen million, one hundred fourteen thousand, one hundred thirty-three".

Divisors: 1 599 526067 315114133