Base | Representation |
---|---|
bin | 100011110100110000100000… |
… | …0100101011110110100101111 |
3 | 1112022201121221110210121111112 |
4 | 1013221201000211132310233 |
5 | 312300312432444442320 |
6 | 3034105252454142235 |
7 | 123242152504102133 |
oct | 10751410045366457 |
9 | 1468647843717445 |
10 | 315114244140335 |
11 | 91450222895602 |
12 | 2b41330295197b |
13 | 106aa1b81b3423 |
14 | 57b587a0373c3 |
15 | 2666ca09b8ec5 |
hex | 11e984095ed2f |
315114244140335 has 32 divisors (see below), whose sum is σ = 406046141246592. Its totient is φ = 233923644702720.
The previous prime is 315114244140263. The next prime is 315114244140359. The reversal of 315114244140335 is 533041442411513.
It is not a de Polignac number, because 315114244140335 - 210 = 315114244139311 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 315114244140292 and 315114244140301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 70490936 + ... + 74827805.
It is an arithmetic number, because the mean of its divisors is an integer number (12688941913956).
Almost surely, 2315114244140335 is an apocalyptic number.
315114244140335 is a deficient number, since it is larger than the sum of its proper divisors (90931897106257).
315114244140335 is a wasteful number, since it uses less digits than its factorization.
315114244140335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145319123.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 315114244140335 its reverse (533041442411513), we get a palindrome (848155686551848).
The spelling of 315114244140335 in words is "three hundred fifteen trillion, one hundred fourteen billion, two hundred forty-four million, one hundred forty thousand, three hundred thirty-five".
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