Search a number
-
+
31513105423 is a prime number
BaseRepresentation
bin11101010110010100…
…111101010000001111
310000100012110121210201
4131112110331100033
51004014323333143
622251003114331
72163631655632
oct352624752017
9100305417721
1031513105423
1112401365588
1261358129a7
132c829c5557
14174d39dc19
15c468b164d
hex75653d40f

31513105423 has 2 divisors, whose sum is σ = 31513105424. Its totient is φ = 31513105422.

The previous prime is 31513105417. The next prime is 31513105453. The reversal of 31513105423 is 32450131513.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (32450131513) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31513105423 is a prime.

It is a super-2 number, since 2×315131054232 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31513105391 and 31513105400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31513105453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15756552711 + 15756552712.

It is an arithmetic number, because the mean of its divisors is an integer number (15756552712).

Almost surely, 231513105423 is an apocalyptic number.

31513105423 is a deficient number, since it is larger than the sum of its proper divisors (1).

31513105423 is an equidigital number, since it uses as much as digits as its factorization.

31513105423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 31513105423 its reverse (32450131513), we get a palindrome (63963236936).

The spelling of 31513105423 in words is "thirty-one billion, five hundred thirteen million, one hundred five thousand, four hundred twenty-three".