Base | Representation |
---|---|
bin | 11101010110010101… |
… | …100100111111101111 |
3 | 10000100012202220002202 |
4 | 131112111210333233 |
5 | 1004014344040312 |
6 | 22251010412115 |
7 | 2163633234341 |
oct | 352625447757 |
9 | 100305686082 |
10 | 31513268207 |
11 | 12401466913 |
12 | 613589103b |
13 | 2c82a51685 |
14 | 174d403291 |
15 | c468e49c2 |
hex | 756564fef |
31513268207 has 2 divisors, whose sum is σ = 31513268208. Its totient is φ = 31513268206.
The previous prime is 31513268179. The next prime is 31513268239. The reversal of 31513268207 is 70286231513.
It is a weak prime.
It is an emirp because it is prime and its reverse (70286231513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31513268207 - 214 = 31513251823 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31513265207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15756634103 + 15756634104.
It is an arithmetic number, because the mean of its divisors is an integer number (15756634104).
Almost surely, 231513268207 is an apocalyptic number.
31513268207 is a deficient number, since it is larger than the sum of its proper divisors (1).
31513268207 is an equidigital number, since it uses as much as digits as its factorization.
31513268207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 38.
The spelling of 31513268207 in words is "thirty-one billion, five hundred thirteen million, two hundred sixty-eight thousand, two hundred seven".
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