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315134051 is a prime number
BaseRepresentation
bin10010110010001…
…001000001100011
3210221222110122112
4102302021001203
51121133242201
651134225535
710544411111
oct2262110143
9727873575
10315134051
11151980971
12896552ab
135039946b
142dbd2ab1
151c9ed0bb
hex12c89063

315134051 has 2 divisors, whose sum is σ = 315134052. Its totient is φ = 315134050.

The previous prime is 315134033. The next prime is 315134059. The reversal of 315134051 is 150431513.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 315134051 - 222 = 310939747 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (315134059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157567025 + 157567026.

It is an arithmetic number, because the mean of its divisors is an integer number (157567026).

Almost surely, 2315134051 is an apocalyptic number.

315134051 is a deficient number, since it is larger than the sum of its proper divisors (1).

315134051 is an equidigital number, since it uses as much as digits as its factorization.

315134051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 315134051 is about 17752.0154067081. The cubic root of 315134051 is about 680.5057159339.

Adding to 315134051 its reverse (150431513), we get a palindrome (465565564).

The spelling of 315134051 in words is "three hundred fifteen million, one hundred thirty-four thousand, fifty-one".