Base | Representation |
---|---|
bin | 1110010101001010010100… |
… | …11010100010100100111111 |
3 | 11010120122122200001110210021 |
4 | 13022211022122202210333 |
5 | 13112303442410201421 |
6 | 151005022241353011 |
7 | 6431525004152566 |
oct | 712451232424477 |
9 | 133518580043707 |
10 | 31513423522111 |
11 | a04a84a030273 |
12 | 364b619938767 |
13 | 147791a8b343b |
14 | 7ad38770abdd |
15 | 399b0a883341 |
hex | 1ca94a6a293f |
31513423522111 has 2 divisors, whose sum is σ = 31513423522112. Its totient is φ = 31513423522110.
The previous prime is 31513423521997. The next prime is 31513423522153. The reversal of 31513423522111 is 11122532431513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31513423522111 - 211 = 31513423520063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31513423526111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15756711761055 + 15756711761056.
It is an arithmetic number, because the mean of its divisors is an integer number (15756711761056).
Almost surely, 231513423522111 is an apocalyptic number.
31513423522111 is a deficient number, since it is larger than the sum of its proper divisors (1).
31513423522111 is an equidigital number, since it uses as much as digits as its factorization.
31513423522111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21600, while the sum is 34.
Adding to 31513423522111 its reverse (11122532431513), we get a palindrome (42635955953624).
The spelling of 31513423522111 in words is "thirty-one trillion, five hundred thirteen billion, four hundred twenty-three million, five hundred twenty-two thousand, one hundred eleven".
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