Base | Representation |
---|---|
bin | 11101010110010110… |
… | …010010101110001101 |
3 | 10000100020010102000120 |
4 | 131112112102232031 |
5 | 1004014421034001 |
6 | 22251014415153 |
7 | 2163634644363 |
oct | 352626225615 |
9 | 100306112016 |
10 | 31513455501 |
11 | 12401584600 |
12 | 61359614b9 |
13 | 2c82ab89b8 |
14 | 174d451633 |
15 | c46930236 |
hex | 756592b8d |
31513455501 has 24 divisors (see below), whose sum is σ = 46195326240. Its totient is φ = 19094797920.
The previous prime is 31513455469. The next prime is 31513455517. The reversal of 31513455501 is 10555431513.
It is not a de Polignac number, because 31513455501 - 25 = 31513455469 is a prime.
It is a super-2 number, since 2×315134555012 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31513455541) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2539530 + ... + 2551908.
It is an arithmetic number, because the mean of its divisors is an integer number (1924805260).
Almost surely, 231513455501 is an apocalyptic number.
It is an amenable number.
31513455501 is a deficient number, since it is larger than the sum of its proper divisors (14681870739).
31513455501 is a wasteful number, since it uses less digits than its factorization.
31513455501 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19417 (or 19406 counting only the distinct ones).
The product of its (nonzero) digits is 22500, while the sum is 33.
The spelling of 31513455501 in words is "thirty-one billion, five hundred thirteen million, four hundred fifty-five thousand, five hundred one".
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