Base | Representation |
---|---|
bin | 1011101111010110… |
… | …1001000010110001 |
3 | 22010121220202122122 |
4 | 2323311221002301 |
5 | 22423224314022 |
6 | 1240413244025 |
7 | 141044316263 |
oct | 27365510261 |
9 | 8117822578 |
10 | 3151401137 |
11 | 137797a355 |
12 | 73b493615 |
13 | 3b2b84101 |
14 | 21c777b33 |
15 | 1369ed742 |
hex | bbd690b1 |
3151401137 has 2 divisors, whose sum is σ = 3151401138. Its totient is φ = 3151401136.
The previous prime is 3151401059. The next prime is 3151401139. The reversal of 3151401137 is 7311041513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2607532096 + 543869041 = 51064^2 + 23321^2 .
It is a cyclic number.
It is not a de Polignac number, because 3151401137 - 28 = 3151400881 is a prime.
Together with 3151401139, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3151401139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1575700568 + 1575700569.
It is an arithmetic number, because the mean of its divisors is an integer number (1575700569).
Almost surely, 23151401137 is an apocalyptic number.
It is an amenable number.
3151401137 is a deficient number, since it is larger than the sum of its proper divisors (1).
3151401137 is an equidigital number, since it uses as much as digits as its factorization.
3151401137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 26.
The square root of 3151401137 is about 56137.3417343572. The cubic root of 3151401137 is about 1466.1145229905.
The spelling of 3151401137 in words is "three billion, one hundred fifty-one million, four hundred one thousand, one hundred thirty-seven".
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