Base | Representation |
---|---|
bin | 1001001010111111101… |
… | …11111111001111100101 |
3 | 1010010102201121212122222 |
4 | 10211133313333033211 |
5 | 20130402112000333 |
6 | 400435052002125 |
7 | 31524330236234 |
oct | 4453767771745 |
9 | 1103381555588 |
10 | 315141125093 |
11 | 111717a49723 |
12 | 510b0160345 |
13 | 2394398a122 |
14 | 11377dc0b1b |
15 | 82e6a9d298 |
hex | 495fdff3e5 |
315141125093 has 2 divisors, whose sum is σ = 315141125094. Its totient is φ = 315141125092.
The previous prime is 315141125077. The next prime is 315141125107. The reversal of 315141125093 is 390521141513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 225927201124 + 89213923969 = 475318^2 + 298687^2 .
It is an emirp because it is prime and its reverse (390521141513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 315141125093 - 24 = 315141125077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315141125693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157570562546 + 157570562547.
It is an arithmetic number, because the mean of its divisors is an integer number (157570562547).
Almost surely, 2315141125093 is an apocalyptic number.
It is an amenable number.
315141125093 is a deficient number, since it is larger than the sum of its proper divisors (1).
315141125093 is an equidigital number, since it uses as much as digits as its factorization.
315141125093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16200, while the sum is 35.
The spelling of 315141125093 in words is "three hundred fifteen billion, one hundred forty-one million, one hundred twenty-five thousand, ninety-three".
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