Base | Representation |
---|---|
bin | 1001001010111111101… |
… | …11111111001111110011 |
3 | 1010010102201121212200111 |
4 | 10211133313333033303 |
5 | 20130402112000412 |
6 | 400435052002151 |
7 | 31524330236254 |
oct | 4453767771763 |
9 | 1103381555614 |
10 | 315141125107 |
11 | 111717a49736 |
12 | 510b0160357 |
13 | 2394398a133 |
14 | 11377dc0b2b |
15 | 82e6a9d2a7 |
hex | 495fdff3f3 |
315141125107 has 2 divisors, whose sum is σ = 315141125108. Its totient is φ = 315141125106.
The previous prime is 315141125093. The next prime is 315141125111. The reversal of 315141125107 is 701521141513.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-315141125107 is a prime.
It is a super-2 number, since 2×3151411251072 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (315141125137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157570562553 + 157570562554.
It is an arithmetic number, because the mean of its divisors is an integer number (157570562554).
Almost surely, 2315141125107 is an apocalyptic number.
315141125107 is a deficient number, since it is larger than the sum of its proper divisors (1).
315141125107 is an equidigital number, since it uses as much as digits as its factorization.
315141125107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 31.
The spelling of 315141125107 in words is "three hundred fifteen billion, one hundred forty-one million, one hundred twenty-five thousand, one hundred seven".
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