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315141400315 = 579004040009
BaseRepresentation
bin1001001010111111110…
…01000010011011111011
31010010102202010212012101
410211133321002123323
520130402144302230
6400435101524231
731524332463520
oct4453771023373
91103382125171
10315141400315
11111718117485
12510b0273677
1323943a55491
1411378053147
1582e6b04aca
hex495fe426fb

315141400315 has 8 divisors (see below), whose sum is σ = 432193920480. Its totient is φ = 216096960192.

The previous prime is 315141400309. The next prime is 315141400349. The reversal of 315141400315 is 513004141513.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 315141400315 - 29 = 315141399803 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4502019970 + ... + 4502020039.

It is an arithmetic number, because the mean of its divisors is an integer number (54024240060).

Almost surely, 2315141400315 is an apocalyptic number.

315141400315 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

315141400315 is a deficient number, since it is larger than the sum of its proper divisors (117052520165).

315141400315 is an equidigital number, since it uses as much as digits as its factorization.

315141400315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9004040021.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 315141400315 its reverse (513004141513), we get a palindrome (828145541828).

The spelling of 315141400315 in words is "three hundred fifteen billion, one hundred forty-one million, four hundred thousand, three hundred fifteen".

Divisors: 1 5 7 35 9004040009 45020200045 63028280063 315141400315