Base | Representation |
---|---|
bin | 1110010101001011110100… |
… | …10001110100101101011110 |
3 | 11010120201201122002011222111 |
4 | 13022211322101310231132 |
5 | 13112312113443342304 |
6 | 151005234045104234 |
7 | 6431553624551644 |
oct | 712457221645536 |
9 | 133521648064874 |
10 | 31514226543454 |
11 | a050121345076 |
12 | 364b80285807a |
13 | 1477a180835b5 |
14 | 7ad422221194 |
15 | 399b56105704 |
hex | 1ca97a474b5e |
31514226543454 has 4 divisors (see below), whose sum is σ = 47271339815184. Its totient is φ = 15757113271726.
The previous prime is 31514226543451. The next prime is 31514226543461. The reversal of 31514226543454 is 45434562241513.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 31514226543398 and 31514226543407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31514226543451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7878556635862 + ... + 7878556635865.
It is an arithmetic number, because the mean of its divisors is an integer number (11817834953796).
Almost surely, 231514226543454 is an apocalyptic number.
31514226543454 is a deficient number, since it is larger than the sum of its proper divisors (15757113271730).
31514226543454 is a wasteful number, since it uses less digits than its factorization.
31514226543454 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15757113271729.
The product of its digits is 6912000, while the sum is 49.
Adding to 31514226543454 its reverse (45434562241513), we get a palindrome (76948788784967).
The spelling of 31514226543454 in words is "thirty-one trillion, five hundred fourteen billion, two hundred twenty-six million, five hundred forty-three thousand, four hundred fifty-four".
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