Search a number
-
+
315144510455 = 563028902091
BaseRepresentation
bin1001001011000000001…
…00111001101111110111
31010010102221222212111202
410211200010321233313
520130403443313310
6400435252323115
731524401066135
oct4454004715767
91103387885452
10315144510455
11111719951145
12510b131349b
13239445a3cb8
1411378622755
1582e701b3a5
hex4960139bf7

315144510455 has 4 divisors (see below), whose sum is σ = 378173412552. Its totient is φ = 252115608360.

The previous prime is 315144510431. The next prime is 315144510503. The reversal of 315144510455 is 554015441513.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 554015441513 = 3625115282763.

It is not a de Polignac number, because 315144510455 - 210 = 315144509431 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31514451041 + ... + 31514451050.

It is an arithmetic number, because the mean of its divisors is an integer number (94543353138).

Almost surely, 2315144510455 is an apocalyptic number.

315144510455 is a deficient number, since it is larger than the sum of its proper divisors (63028902097).

315144510455 is an equidigital number, since it uses as much as digits as its factorization.

315144510455 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63028902096.

The product of its (nonzero) digits is 120000, while the sum is 38.

Adding to 315144510455 its reverse (554015441513), we get a palindrome (869159951968).

The spelling of 315144510455 in words is "three hundred fifteen billion, one hundred forty-four million, five hundred ten thousand, four hundred fifty-five".

Divisors: 1 5 63028902091 315144510455