Base | Representation |
---|---|
bin | 11101010110011101… |
… | …011000011110000011 |
3 | 10000100100121211110202 |
4 | 131112131120132003 |
5 | 1004020410022201 |
6 | 22251122315415 |
7 | 2163656515034 |
oct | 352635303603 |
9 | 100310554422 |
10 | 31515314051 |
11 | 124026339a1 |
12 | 61364b8b6b |
13 | 2c832b9930 |
14 | 174d7b6a8b |
15 | c46b9ac6b |
hex | 756758783 |
31515314051 has 32 divisors (see below), whose sum is σ = 36674322048. Its totient is φ = 26819020800.
The previous prime is 31515314027. The next prime is 31515314123. The reversal of 31515314051 is 15041351513.
It is a de Polignac number, because none of the positive numbers 2k-31515314051 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31515314011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8513501 + ... + 8517201.
It is an arithmetic number, because the mean of its divisors is an integer number (1146072564).
Almost surely, 231515314051 is an apocalyptic number.
31515314051 is a deficient number, since it is larger than the sum of its proper divisors (5159007997).
31515314051 is a wasteful number, since it uses less digits than its factorization.
31515314051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4511.
The product of its (nonzero) digits is 4500, while the sum is 29.
Adding to 31515314051 its reverse (15041351513), we get a palindrome (46556665564).
The spelling of 31515314051 in words is "thirty-one billion, five hundred fifteen million, three hundred fourteen thousand, fifty-one".
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