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315231131045 = 563046226209
BaseRepresentation
bin1001001011001010011…
…11010101010110100101
31010010122222222122121202
410211211033111112211
520131043132143140
6400452025052245
731526502255245
oct4454517252645
91103588878552
10315231131045
11111763834506
1251116327085
132395951199c
1411385d2db25
1582ee92b915
hex49653d55a5

315231131045 has 4 divisors (see below), whose sum is σ = 378277357260. Its totient is φ = 252184904832.

The previous prime is 315231131003. The next prime is 315231131071. The reversal of 315231131045 is 540131132513.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 78418481089 + 236812649956 = 280033^2 + 486634^2 .

It is a cyclic number.

It is not a de Polignac number, because 315231131045 - 212 = 315231126949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 315231130999 and 315231131017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31523113100 + ... + 31523113109.

It is an arithmetic number, because the mean of its divisors is an integer number (94569339315).

Almost surely, 2315231131045 is an apocalyptic number.

It is an amenable number.

315231131045 is a deficient number, since it is larger than the sum of its proper divisors (63046226215).

315231131045 is an equidigital number, since it uses as much as digits as its factorization.

315231131045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63046226214.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 315231131045 its reverse (540131132513), we get a palindrome (855362263558).

The spelling of 315231131045 in words is "three hundred fifteen billion, two hundred thirty-one million, one hundred thirty-one thousand, forty-five".

Divisors: 1 5 63046226209 315231131045