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31540342030 = 253154034203
BaseRepresentation
bin11101010111111100…
…110110110100001110
310000102002201101101221
4131113330312310032
51004043311421110
622253414553554
72164412324641
oct352774666416
9100362641357
1031540342030
111241577887a
1261429688ba
132c885407a2
141752c4da58
15c48e917da
hex757f36d0e

31540342030 has 8 divisors (see below), whose sum is σ = 56772615672. Its totient is φ = 12616136808.

The previous prime is 31540342027. The next prime is 31540342033. The reversal of 31540342030 is 3024304513.

It is an interprime number because it is at equal distance from previous prime (31540342027) and next prime (31540342033).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 31540341986 and 31540342004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31540342033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1577017092 + ... + 1577017111.

It is an arithmetic number, because the mean of its divisors is an integer number (7096576959).

Almost surely, 231540342030 is an apocalyptic number.

31540342030 is a deficient number, since it is larger than the sum of its proper divisors (25232273642).

31540342030 is a wasteful number, since it uses less digits than its factorization.

31540342030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3154034210.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 31540342030 its reverse (3024304513), we get a palindrome (34564646543).

The spelling of 31540342030 in words is "thirty-one billion, five hundred forty million, three hundred forty-two thousand, thirty".

Divisors: 1 2 5 10 3154034203 6308068406 15770171015 31540342030