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315500240045 = 563100048009
BaseRepresentation
bin1001001011101010100…
…01111001110010101101
31010011100202100210202202
410211311101321302231
520132121030140140
6400534441031245
731536250535504
oct4456521716255
91104322323682
10315500240045
1111189172a041
1251190485525
13239a01b5093
14113ad98183b
158318387915
hex4975479cad

315500240045 has 4 divisors (see below), whose sum is σ = 378600288060. Its totient is φ = 252400192032.

The previous prime is 315500240023. The next prime is 315500240047. The reversal of 315500240045 is 540042005513.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 241384533481 + 74115706564 = 491309^2 + 272242^2 .

It is a cyclic number.

It is not a de Polignac number, because 315500240045 - 236 = 246780763309 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315500240047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31550024000 + ... + 31550024009.

It is an arithmetic number, because the mean of its divisors is an integer number (94650072015).

Almost surely, 2315500240045 is an apocalyptic number.

It is an amenable number.

315500240045 is a deficient number, since it is larger than the sum of its proper divisors (63100048015).

315500240045 is an equidigital number, since it uses as much as digits as its factorization.

315500240045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63100048014.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 315500240045 its reverse (540042005513), we get a palindrome (855542245558).

The spelling of 315500240045 in words is "three hundred fifteen billion, five hundred million, two hundred forty thousand, forty-five".

Divisors: 1 5 63100048009 315500240045