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315500363113 = 13171427603453
BaseRepresentation
bin1001001011101010100…
…10010111110101101001
31010011100202121001120211
410211311102113311221
520132121043104423
6400534443421121
731536251560345
oct4456522276551
91104322531524
10315500363113
11111891803551
12511905247a1
13239a02290c0
14113ad9b4625
1583183ae10d
hex4975497d69

315500363113 has 8 divisors (see below), whose sum is σ = 359756070408. Its totient is φ = 274099862784.

The previous prime is 315500363069. The next prime is 315500363203. The reversal of 315500363113 is 311363005513.

It can be written as a sum of positive squares in 4 ways, for example, as 6953769 + 315493409344 = 2637^2 + 561688^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315500363113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (315500363513) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 713801506 + ... + 713801947.

It is an arithmetic number, because the mean of its divisors is an integer number (44969508801).

Almost surely, 2315500363113 is an apocalyptic number.

It is an amenable number.

315500363113 is a deficient number, since it is larger than the sum of its proper divisors (44255707295).

315500363113 is a wasteful number, since it uses less digits than its factorization.

315500363113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1427603483.

The product of its (nonzero) digits is 12150, while the sum is 31.

Adding to 315500363113 its reverse (311363005513), we get a palindrome (626863368626).

The spelling of 315500363113 in words is "three hundred fifteen billion, five hundred million, three hundred sixty-three thousand, one hundred thirteen".

Divisors: 1 13 17 221 1427603453 18558844889 24269258701 315500363113