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315654250013 is a prime number
BaseRepresentation
bin1001001011111100111…
…01011001111000011101
31010011202111011022201122
410211332131121320131
520132424442000023
6401002022020325
731543130566244
oct4457635317035
91104674138648
10315654250013
11111960660003
1251213b776a5
13239c608923b
14113c61d195b
158326b5a2c8
hex497e759e1d

315654250013 has 2 divisors, whose sum is σ = 315654250014. Its totient is φ = 315654250012.

The previous prime is 315654249979. The next prime is 315654250069. The reversal of 315654250013 is 310052456513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 310412779609 + 5241470404 = 557147^2 + 72398^2 .

It is a cyclic number.

It is not a de Polignac number, because 315654250013 - 210 = 315654248989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315654150013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157827125006 + 157827125007.

It is an arithmetic number, because the mean of its divisors is an integer number (157827125007).

Almost surely, 2315654250013 is an apocalyptic number.

It is an amenable number.

315654250013 is a deficient number, since it is larger than the sum of its proper divisors (1).

315654250013 is an equidigital number, since it uses as much as digits as its factorization.

315654250013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54000, while the sum is 35.

The spelling of 315654250013 in words is "three hundred fifteen billion, six hundred fifty-four million, two hundred fifty thousand, thirteen".