Base | Representation |
---|---|
bin | 101101111100100010000… |
… | …011010010111111000111 |
3 | 102011211201200220222222212 |
4 | 231330202003102333013 |
5 | 403212244244031403 |
6 | 10414250553014035 |
7 | 444053425220516 |
oct | 55744203227707 |
9 | 12154650828885 |
10 | 3157372252103 |
11 | 1008041361a63 |
12 | 42bb056b431b |
13 | 19b97b55c9c4 |
14 | acb6382467d |
15 | 571e566e4d8 |
hex | 2df220d2fc7 |
3157372252103 has 2 divisors, whose sum is σ = 3157372252104. Its totient is φ = 3157372252102.
The previous prime is 3157372252087. The next prime is 3157372252109. The reversal of 3157372252103 is 3012522737513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3157372252103 - 24 = 3157372252087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3157372252109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1578686126051 + 1578686126052.
It is an arithmetic number, because the mean of its divisors is an integer number (1578686126052).
Almost surely, 23157372252103 is an apocalyptic number.
3157372252103 is a deficient number, since it is larger than the sum of its proper divisors (1).
3157372252103 is an equidigital number, since it uses as much as digits as its factorization.
3157372252103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 264600, while the sum is 41.
Adding to 3157372252103 its reverse (3012522737513), we get a palindrome (6169894989616).
The spelling of 3157372252103 in words is "three trillion, one hundred fifty-seven billion, three hundred seventy-two million, two hundred fifty-two thousand, one hundred three".
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