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315850142047 = 1128713649277
BaseRepresentation
bin1001001100010100010…
…00101011000101011111
31010012021010202200002011
410212022020223011133
520133330114021142
6401033300412051
731551026624116
oct4461210530537
91105233680064
10315850142047
11111a51197650
12512696a7027
1323a2783579b
1411404224c7d
158338e52417
hex498a22b15f

315850142047 has 4 divisors (see below), whose sum is σ = 344563791336. Its totient is φ = 287136492760.

The previous prime is 315850142021. The next prime is 315850142059. The reversal of 315850142047 is 740241058513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 315850142047 - 215 = 315850109279 is a prime.

It is a super-2 number, since 2×3158501420472 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315850142747) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14356824628 + ... + 14356824649.

It is an arithmetic number, because the mean of its divisors is an integer number (86140947834).

Almost surely, 2315850142047 is an apocalyptic number.

315850142047 is a deficient number, since it is larger than the sum of its proper divisors (28713649289).

315850142047 is a wasteful number, since it uses less digits than its factorization.

315850142047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28713649288.

The product of its (nonzero) digits is 134400, while the sum is 40.

The spelling of 315850142047 in words is "three hundred fifteen billion, eight hundred fifty million, one hundred forty-two thousand, forty-seven".

Divisors: 1 11 28713649277 315850142047