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3160242047135 = 5632048409427
BaseRepresentation
bin101101111111001101000…
…110101100100010011111
3102012010010200221200200202
4231333031012230202133
5403234133431002020
610415443430414115
7444214513120055
oct55771506544237
912163120850622
103160242047135
111009284280498
1243058680133b
1319c017c86384
14acd56a161d5
1557312593e75
hex2dfcd1ac89f

3160242047135 has 4 divisors (see below), whose sum is σ = 3792290456568. Its totient is φ = 2528193637704.

The previous prime is 3160242047117. The next prime is 3160242047173. The reversal of 3160242047135 is 5317402420613.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3160242047135 - 28 = 3160242046879 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316024204709 + ... + 316024204718.

It is an arithmetic number, because the mean of its divisors is an integer number (948072614142).

Almost surely, 23160242047135 is an apocalyptic number.

3160242047135 is a deficient number, since it is larger than the sum of its proper divisors (632048409433).

3160242047135 is an equidigital number, since it uses as much as digits as its factorization.

3160242047135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 632048409432.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 3160242047135 its reverse (5317402420613), we get a palindrome (8477644467748).

The spelling of 3160242047135 in words is "three trillion, one hundred sixty billion, two hundred forty-two million, forty-seven thousand, one hundred thirty-five".

Divisors: 1 5 632048409427 3160242047135