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3161289900000 = 2535510121033
BaseRepresentation
bin101110000000001011100…
…011111011111111100000
3102012012211201200010121010
4232000023203323333200
5403243310203300000
610420135421500520
7444252465533511
oct56001343737740
912165751603533
103161289900000
1110097718088a1
12430819711740
1319c1540a955b
14ad015c5ca08
1557374578d50
hex2e00b8fbfe0

3161289900000 has 432 divisors, whose sum is σ = 10486172998224. Its totient is φ = 833856000000.

The previous prime is 3161289899959. The next prime is 3161289900017. The reversal of 3161289900000 is 99821613.

It is a super-3 number, since 3×31612899000003 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 3060299484 + ... + 3060300516.

It is an arithmetic number, because the mean of its divisors is an integer number (24273548607).

Almost surely, 23161289900000 is an apocalyptic number.

3161289900000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3161289900000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5243086499112).

3161289900000 is an abundant number, since it is smaller than the sum of its proper divisors (7324883098224).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3161289900000 is an equidigital number, since it uses as much as digits as its factorization.

3161289900000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1273 (or 1144 counting only the distinct ones).

The product of its (nonzero) digits is 23328, while the sum is 39.

The spelling of 3161289900000 in words is "three trillion, one hundred sixty-one billion, two hundred eighty-nine million, nine hundred thousand".