3162340255113 has 48 divisors (see below), whose sum is σ = 4975381022976. Its totient is φ = 1923872670720.

The previous prime is 3162340255111. The next prime is 3162340255141. The reversal of 3162340255113 is 3115520432613.

3162340255113 is a `hidden beast` number, since 3 + 1 + 62 + 3 + 40 + 2 + 551 + 1 + 3 = 666.

It is not a de Polignac number, because 3162340255113 - 2¹ = 3162340255111 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3162340255111) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10186006 + ... + 10491872.

It is an arithmetic number, because the mean of its divisors is an integer number (103653771312).

Almost surely, 2^{3162340255113} is an apocalyptic number.

It is an amenable number.

3162340255113 is a deficient number, since it is larger than the sum of its proper divisors (1813040767863).

3162340255113 is a wasteful number, since it uses less digits than its factorization.

3162340255113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 306894 (or 306891 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 36.

Adding to 3162340255113 its reverse (3115520432613), we get a palindrome (6277860687726).

The spelling of 3162340255113 in words is "three trillion, one hundred sixty-two billion, three hundred forty million, two hundred fifty-five thousand, one hundred thirteen".