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316241142613 = 1128749194783
BaseRepresentation
bin1001001101000010111…
…00001110001101010101
31010020021101111120000121
410212201130032031111
520140130213030423
6401140145111541
731563515234344
oct4464134161525
91106241446017
10316241142613
11112131976110
12513586285b1
1323a8a845a76
1411440125b5b
15835d43945d
hex49a170e355

316241142613 has 4 divisors (see below), whose sum is σ = 344990337408. Its totient is φ = 287491947820.

The previous prime is 316241142593. The next prime is 316241142619.

316241142613 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-316241142613 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (316241142619) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14374597381 + ... + 14374597402.

It is an arithmetic number, because the mean of its divisors is an integer number (86247584352).

Almost surely, 2316241142613 is an apocalyptic number.

It is an amenable number.

316241142613 is a deficient number, since it is larger than the sum of its proper divisors (28749194795).

316241142613 is a wasteful number, since it uses less digits than its factorization.

316241142613 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28749194794.

The product of its digits is 20736, while the sum is 34.

It can be divided in two parts, 316241 and 142613, that added together give a palindrome (458854).

The spelling of 316241142613 in words is "three hundred sixteen billion, two hundred forty-one million, one hundred forty-two thousand, six hundred thirteen".

Divisors: 1 11 28749194783 316241142613