Base | Representation |
---|---|
bin | 101110100100001111100… |
… | …101011010001000011001 |
3 | 102022220210100022201012011 |
4 | 232210033211122020121 |
5 | 404412111044200441 |
6 | 10450022032545521 |
7 | 450123166025314 |
oct | 56441745321031 |
9 | 12286710281164 |
10 | 3200012100121 |
11 | 1024132451981 |
12 | 4382256b22a1 |
13 | 1a29b54c77c5 |
14 | b0c4a84797b |
15 | 5838dca8581 |
hex | 2e90f95a219 |
3200012100121 has 2 divisors, whose sum is σ = 3200012100122. Its totient is φ = 3200012100120.
The previous prime is 3200012100097. The next prime is 3200012100137. The reversal of 3200012100121 is 1210012100023.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1717766724496 + 1482245375625 = 1310636^2 + 1217475^2 .
It is an emirp because it is prime and its reverse (1210012100023) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3200012100121 is a prime.
It is not a weakly prime, because it can be changed into another prime (3200012100161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600006050060 + 1600006050061.
It is an arithmetic number, because the mean of its divisors is an integer number (1600006050061).
Almost surely, 23200012100121 is an apocalyptic number.
It is an amenable number.
3200012100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3200012100121 is an equidigital number, since it uses as much as digits as its factorization.
3200012100121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 3200012100121 its reverse (1210012100023), we get a palindrome (4410024200144).
The spelling of 3200012100121 in words is "three trillion, two hundred billion, twelve million, one hundred thousand, one hundred twenty-one".
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