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1210012100023 is a prime number
BaseRepresentation
bin10001100110111010010…
…101110110010110110111
311021200020211020111012211
4101212322111312112313
5124311101044200043
62323512154354251
7153264141102016
oct21467225662667
94250224214184
101210012100023
11427188316021
1217661272b987
138a14695084c
14427ca11aa7d
152171db88a9d
hex119ba5765b7

1210012100023 has 2 divisors, whose sum is σ = 1210012100024. Its totient is φ = 1210012100022.

The previous prime is 1210012100009. The next prime is 1210012100041. The reversal of 1210012100023 is 3200012100121.

It is a weak prime.

It is an emirp because it is prime and its reverse (3200012100121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1210012100023 - 25 = 1210012099991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1210012099976 and 1210012100012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210012100093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605006050011 + 605006050012.

It is an arithmetic number, because the mean of its divisors is an integer number (605006050012).

Almost surely, 21210012100023 is an apocalyptic number.

1210012100023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210012100023 is an equidigital number, since it uses as much as digits as its factorization.

1210012100023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1210012100023 its reverse (3200012100121), we get a palindrome (4410024200144).

The spelling of 1210012100023 in words is "one trillion, two hundred ten billion, twelve million, one hundred thousand, twenty-three".