Base | Representation |
---|---|
bin | 1001010100000011001… |
… | …00000101011010000111 |
3 | 1010120222102220100101211 |
4 | 10222001210011122013 |
5 | 20220330313100403 |
6 | 403001230232251 |
7 | 32055634112542 |
oct | 4520144053207 |
9 | 1116872810354 |
10 | 320001300103 |
11 | 113791434091 |
12 | 52027955687 |
13 | 24239870224 |
14 | 116b9685859 |
15 | 84cd5d506d |
hex | 4a81905687 |
320001300103 has 2 divisors, whose sum is σ = 320001300104. Its totient is φ = 320001300102.
The previous prime is 320001300097. The next prime is 320001300127. The reversal of 320001300103 is 301003100023.
It is a weak prime.
It is an emirp because it is prime and its reverse (301003100023) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 320001300103 - 25 = 320001300071 is a prime.
It is a super-2 number, since 2×3200013001032 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (320001300163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160000650051 + 160000650052.
It is an arithmetic number, because the mean of its divisors is an integer number (160000650052).
Almost surely, 2320001300103 is an apocalyptic number.
320001300103 is a deficient number, since it is larger than the sum of its proper divisors (1).
320001300103 is an equidigital number, since it uses as much as digits as its factorization.
320001300103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 320001300103 its reverse (301003100023), we get a palindrome (621004400126).
The spelling of 320001300103 in words is "three hundred twenty billion, one million, three hundred thousand, one hundred three".
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