Base | Representation |
---|---|
bin | 101110100100010111001… |
… | …101101100010110011111 |
3 | 102022221010021011211102022 |
4 | 232210113031230112133 |
5 | 404412341331213043 |
6 | 10450042444250355 |
7 | 450126312021635 |
oct | 56442715542637 |
9 | 12287107154368 |
10 | 3200140101023 |
11 | 1024198728948 |
12 | 4382605409bb |
13 | 1a2a05b93398 |
14 | b0c5d847355 |
15 | 5839a13e868 |
hex | 2e91736c59f |
3200140101023 has 2 divisors, whose sum is σ = 3200140101024. Its totient is φ = 3200140101022.
The previous prime is 3200140100957. The next prime is 3200140101043. The reversal of 3200140101023 is 3201010410023.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3200140101023 - 210 = 3200140099999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3200140100992 and 3200140101010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3200140101043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600070050511 + 1600070050512.
It is an arithmetic number, because the mean of its divisors is an integer number (1600070050512).
Almost surely, 23200140101023 is an apocalyptic number.
3200140101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
3200140101023 is an equidigital number, since it uses as much as digits as its factorization.
3200140101023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 3200140101023 its reverse (3201010410023), we get a palindrome (6401150511046).
The spelling of 3200140101023 in words is "three trillion, two hundred billion, one hundred forty million, one hundred one thousand, twenty-three".
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