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320021322011 is a prime number
BaseRepresentation
bin1001010100000101100…
…00011101100100011011
31010121000211120120021222
410222002300131210123
520220400424301021
6403003223322255
732056266232466
oct4520260354433
91117024516258
10320021322011
111137a1769916
12520325b038b
1324240a60601
14116bc1b82dd
1584d023c6ab
hex4a82c1d91b

320021322011 has 2 divisors, whose sum is σ = 320021322012. Its totient is φ = 320021322010.

The previous prime is 320021321993. The next prime is 320021322013. The reversal of 320021322011 is 110223120023.

It is a strong prime.

It is an emirp because it is prime and its reverse (110223120023) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 320021322011 - 226 = 319954213147 is a prime.

Together with 320021322013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (320021322013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160010661005 + 160010661006.

It is an arithmetic number, because the mean of its divisors is an integer number (160010661006).

Almost surely, 2320021322011 is an apocalyptic number.

320021322011 is a deficient number, since it is larger than the sum of its proper divisors (1).

320021322011 is an equidigital number, since it uses as much as digits as its factorization.

320021322011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 320021322011 its reverse (110223120023), we get a palindrome (430244442034).

The spelling of 320021322011 in words is "three hundred twenty billion, twenty-one million, three hundred twenty-two thousand, eleven".