Base | Representation |
---|---|
bin | 1011111011000010… |
… | …1011111111000101 |
3 | 22021001011220020221 |
4 | 2332300223333011 |
5 | 23023302342432 |
6 | 1245324224341 |
7 | 142211145466 |
oct | 27660537705 |
9 | 8231156227 |
10 | 3200434117 |
11 | 13a261a581 |
12 | 75399b0b1 |
13 | 3c00912ca |
14 | 22509cd6d |
15 | 13ae86b97 |
hex | bec2bfc5 |
3200434117 has 2 divisors, whose sum is σ = 3200434118. Its totient is φ = 3200434116.
The previous prime is 3200434063. The next prime is 3200434187. The reversal of 3200434117 is 7114340023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2720561281 + 479872836 = 52159^2 + 21906^2 .
It is a cyclic number.
It is not a de Polignac number, because 3200434117 - 211 = 3200432069 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3200434091 and 3200434100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3200434187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600217058 + 1600217059.
It is an arithmetic number, because the mean of its divisors is an integer number (1600217059).
Almost surely, 23200434117 is an apocalyptic number.
It is an amenable number.
3200434117 is a deficient number, since it is larger than the sum of its proper divisors (1).
3200434117 is an equidigital number, since it uses as much as digits as its factorization.
3200434117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The square root of 3200434117 is about 56572.3794532279. The cubic root of 3200434117 is about 1473.6792339723.
The spelling of 3200434117 in words is "three billion, two hundred million, four hundred thirty-four thousand, one hundred seventeen".
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