Base | Representation |
---|---|
bin | 101110100101001010100… |
… | …001110000110001110011 |
3 | 102100000100021010000212111 |
4 | 232211022201300301303 |
5 | 404421122224000201 |
6 | 10450304120310151 |
7 | 450156534365431 |
oct | 56451241606163 |
9 | 12300307100774 |
10 | 3201001000051 |
11 | 102459a684048 |
12 | 438460912357 |
13 | 1a2b123494aa |
14 | b0d01d05d51 |
15 | 583ea9e5b51 |
hex | 2e94a870c73 |
3201001000051 has 2 divisors, whose sum is σ = 3201001000052. Its totient is φ = 3201001000050.
The previous prime is 3201001000037. The next prime is 3201001000069. The reversal of 3201001000051 is 1500001001023.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3201001000051 - 27 = 3201000999923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3201000999995 and 3201001000040.
It is not a weakly prime, because it can be changed into another prime (3201001000451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1600500500025 + 1600500500026.
It is an arithmetic number, because the mean of its divisors is an integer number (1600500500026).
Almost surely, 23201001000051 is an apocalyptic number.
3201001000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
3201001000051 is an equidigital number, since it uses as much as digits as its factorization.
3201001000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 13.
Adding to 3201001000051 its reverse (1500001001023), we get a palindrome (4701002001074).
The spelling of 3201001000051 in words is "three trillion, two hundred one billion, one million, fifty-one", and thus it is an aban number.
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