Base | Representation |
---|---|
bin | 11101110100000001… |
… | …110101101011000001 |
3 | 10001121221010010022222 |
4 | 131310001311223001 |
5 | 1011024410110423 |
6 | 22412243340425 |
7 | 2212162332164 |
oct | 356401655301 |
9 | 101557103288 |
10 | 32011410113 |
11 | 12637674241 |
12 | 6254681715 |
13 | 3032005ab7 |
14 | 1799633adb |
15 | c754e23c8 |
hex | 774075ac1 |
32011410113 has 2 divisors, whose sum is σ = 32011410114. Its totient is φ = 32011410112.
The previous prime is 32011410077. The next prime is 32011410133. The reversal of 32011410113 is 31101411023.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16484505664 + 15526904449 = 128392^2 + 124607^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-32011410113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 32011410091 and 32011410100.
It is not a weakly prime, because it can be changed into another prime (32011410133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 16005705056 + 16005705057.
It is an arithmetic number, because the mean of its divisors is an integer number (16005705057).
Almost surely, 232011410113 is an apocalyptic number.
It is an amenable number.
32011410113 is a deficient number, since it is larger than the sum of its proper divisors (1).
32011410113 is an equidigital number, since it uses as much as digits as its factorization.
32011410113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 32011410113 its reverse (31101411023), we get a palindrome (63112821136).
The spelling of 32011410113 in words is "thirty-two billion, eleven million, four hundred ten thousand, one hundred thirteen".
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