Base | Representation |
---|---|
bin | 1001010100010010101… |
… | …11011011101010001101 |
3 | 1010121022120012210210221 |
4 | 10222021113123222031 |
5 | 20221112320413401 |
6 | 403022224031341 |
7 | 32062113545236 |
oct | 4521127335215 |
9 | 1117276183727 |
10 | 320132201101 |
11 | 113849310a29 |
12 | 52063762551 |
13 | 2425aa12b3b |
14 | 116ccbdc08d |
15 | 84d9d407a1 |
hex | 4a895dba8d |
320132201101 has 2 divisors, whose sum is σ = 320132201102. Its totient is φ = 320132201100.
The previous prime is 320132201089. The next prime is 320132201141. The reversal of 320132201101 is 101102231023.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 270115115076 + 50017086025 = 519726^2 + 223645^2 .
It is a cyclic number.
It is not a de Polignac number, because 320132201101 - 229 = 319595330189 is a prime.
It is a super-2 number, since 2×3201322011012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (320132201141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 160066100550 + 160066100551.
It is an arithmetic number, because the mean of its divisors is an integer number (160066100551).
Almost surely, 2320132201101 is an apocalyptic number.
It is an amenable number.
320132201101 is a deficient number, since it is larger than the sum of its proper divisors (1).
320132201101 is an equidigital number, since it uses as much as digits as its factorization.
320132201101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 320132201101 its reverse (101102231023), we get a palindrome (421234432124).
The spelling of 320132201101 in words is "three hundred twenty billion, one hundred thirty-two million, two hundred one thousand, one hundred one".
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